## Calculus with Applications (10th Edition)

$2x-y=-4$
Given the intercepts, we have two points on the line: $(-2,0)$ and $(0,4)$. Slope: $m=\displaystyle \frac{4-0}{0-(-2)}=\frac{4}{2}=2$ Slope-intercept form: $y=mx+b$ (y-intercept: 4) $y=2x+4\qquad/-y-4$ $-4=2x-y$ $2x-y=-4$