## Calculus: Early Transcendentals 8th Edition

The center of this circle is $(3,-5)$ The radius of the circle is $5$
We can write the general equation for a circle: $(x-a)^2+(y-b)^2 = r^2$ where $(a,b)$ is the center of the circle and $r$ is the radius We can rearrange and factor the given equation: $x^2+y^2-6x+10y+9=0$ $x^2-6x+y^2+10y=-9$ $x^2-6x+9+y^2+10y+25=-9+9+25$ $(x-3)^2+(y+5)^2 = 25$ The center of this circle is $(3,-5)$ The radius of the circle is $5$