Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Diagnostic Tests - B Diagnostic Tests: Analytic Geometry - Page xxviii: 3

Answer

The center of this circle is $(3,-5)$ The radius of the circle is $5$

Work Step by Step

We can write the general equation for a circle: $(x-a)^2+(y-b)^2 = r^2$ where $(a,b)$ is the center of the circle and $r$ is the radius We can rearrange and factor the given equation: $x^2+y^2-6x+10y+9=0$ $x^2-6x+y^2+10y=-9$ $x^2-6x+9+y^2+10y+25=-9+9+25$ $(x-3)^2+(y+5)^2 = 25$ The center of this circle is $(3,-5)$ The radius of the circle is $5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.