Answer
$P_L$ is a reasonable accurate model while $P_E$ is not a reasonable accurate model
Work Step by Step
Let suppose choose $t=0$ to correspond to the $1960$ and subract $94000$ from each population figures. Use the calculator to find the model and $94000$ to get the following function,
$P_E(t)=1909.7761(.0796)^t+ 94000$
$P_L(t)=\frac{33086.4394}{1+12.3428e^{-1.1657t}}+94000$
so, $P_L$ is a reasonable accurate model while $P_E$ is not a reasonable accurate model