Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 8 - Section 8.4 - Applications to Economics and Biology - 8.4 Exercises - Page 572: 7

Answer

The producer surplus is $\$166,666.67$

Work Step by Step

We can find the number of units $X$: $p(x) = 125+0.002x^2$ $125+0.002X^2 = 625$ $0.002X^2 = 500$ $X^2 = 250,000$ $X = 500$ We can find the producer surplus: $\int_{0}^{X}[P-p(x)]~dx$ $=\int_{0}^{500}[625-(125+0.002x^2)]~dx$ $=\int_{0}^{500}(500-0.002x^2)~dx$ $=500x-\frac{0.002}{3}x^3~\vert_{0}^{500}$ $= 500(500)-\frac{0.002}{3}(500)^3 - 0$ $= \$166,666.67$ The producer surplus is $\$166,666.67$
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