Answer
$\$140,000$ , $\$60,000$
Work Step by Step
$C(50) - C(0) = \int^{50}_{0} (0.6+0.008x)dx$ then $C(50) = 100+[0.6x + 0.004x^{2}]^{50}_{0} = 100 + (40 - 0) = 140$ or $\$140,000$
Similarly, $C(100) - C(50) = [0.6x + 0.004x^{2}]^{100}_{50} = 60$ or $\$60,000$
