Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 6 - Section 6.4 - Work - 6.4 Exercises - Page 459: 19

Answer

$125\text{ lb}\cdot\text{ft}$

Work Step by Step

The weight is uniformly distributed along the chain. $F= \frac{25\text{ lb}}{10\text{ ft}} = 2.5\text{ lb/ft}$ We’ll integrate over the chain’s length to add up the work. $W =\int_0^{10} 2.5x dx=2.5\int_0^{10}x dx$ $=2.5\left[\frac{x^2}{2}\right]_0^{10}=125$
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