Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 6 - Section 6.1 - Areas Between Curves - 6.1 Exercises - Page 434: 24

Answer

$-\pi$

Work Step by Step

$\int_0^\pi|cos(x)-1+cos(x)|dx=\int_0^\pi|2cos(x)-1|dx=[2\sin(x)-x]_0^\pi=-\pi$
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