Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Section 5.2 - The Definite Integral - 5.2 Exercises - Page 389: 33

Answer

a) 4 b) 10 c) -3 d) 2

Work Step by Step

a) $2(1)+\frac{1}{2}(2\times2)=4$ b) $2(1)+\frac{1}{2}(2\times2)+1(3)+\frac{1}{2}(2)(3)=10$ c) $-\frac{1}{2}(2)(3)=-3$ d) $\int_{0}^{9}f(x)dx=\int_{0}^{5}f(x)dx+\int_{5}^{7}f(x)dx+\int_{7}^{9}f(x)dx$ We already have $\int_{0}^{5}f(x)dx$ and $\int_{5}^{7}f(x)dx$ from parts b and c. $10-3-2(2)-\frac{1}{2}(2)(1)=2$
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