## Calculus: Early Transcendentals 8th Edition

Consider $f(x)=6,g(x)=x, a=-4, b=4$ Therefore, $f(x)\geq g(x)$ on $(-4,4)$ However $f'(x) \leq g'(x)$, since $f'(x)=0$ and $g'(x)=1$ Hence, the statement is false.