Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.8 - Exponential Growth and Decay - 3.8 Exercises - Page 244: 15

Answer

(a) The temperature after 45 minutes is $137^{\circ}F$ (b) The turkey will have cooled to $100^{\circ}F$ after 116 minutes.

Work Step by Step

(a) We can find $k$: $T(t) = 75+110~e^{kt}$ $T(30) = 75+110~e^{30k} = 150$ $110~e^{30k} = 75$ $e^{30k} = \frac{75}{110}$ $30k = ln(\frac{75}{110})$ $k = \frac{ln(\frac{75}{110})}{30}$ $k = -0.0127664$ Then: $T(t) = 75+110~e^{-0.0127664~t}$ We can find the temperature after 45 minutes: $T(t) = 75+110~e^{-0.0127664~t}$ $T(45) = 75+110~e^{(-0.0127664)(45)}$ $T(45) = 137$ The temperature after 45 minutes is $137^{\circ}F$ (b) We can find the time $t$ when the temperature is $100^{\circ}F$: $75+110~e^{-0.0127664~t} = 100$ $e^{-0.0127664~t} = \frac{25}{110}$ $-0.0127664~t = ln(\frac{25}{110})$ $t = \frac{ln(\frac{25}{110})}{-0.0127664}$ $t = 116~minutes$ The turkey will have cooled to $100^{\circ}F$ after 116 minutes.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.