Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.5 - Implicit Differentiation - 3.5 Exercises - Page 216: 50

Answer

$y'=\frac{2x}{1+x^4}$

Work Step by Step

Use the derivative of inverse tangent ($\frac{1}{1+x^2}$) and apply the chain rule to find the derivative of the equation: $y'=\frac{1}{1+(x^2)^2}\times2x=\frac{2x}{1+x^4}$
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