Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.4 - The Chain Rule - 3.4 Exercises - Page 207: 96

Answer

$y=2$

Work Step by Step

The rate of change of $y$ with respect to $x$ is $\frac{dy}{dx}$. Recall that the chain rule says that $\frac{d}{dx}u^n=nu^{n-1}u'$. So the derivative of $y^5$ is as follows. $\frac{d}{dx}y^5=5y^4\frac{dy}{dx}$ Now we set up our equation. $5y^4\frac{dy}{dx}=80\frac{dy}{dx}$ $5y^4=80$ $y^4=16$ $y=2$
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