Answer
$g'(x)=(e^{x^{2}-x})(2x-1)$
Work Step by Step
$g(x)=e^{x^{2}-x}$
Differentiate using the chain rule:
$g'(x)=(e^{x^{2}-x})(x^{2}-x)'=(e^{x^{2}-x})(2x-1)$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 3 - Section 3.4 - The Chain Rule - 3.4 Exercises - Page 204: 16
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