Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.2 - The Product and Quotient Rules - 3.2 Exercises: 48

Answer

$$f''(2)=200$$

Work Step by Step

$f(2)=10$ and $f'(x)=x^2f(x)$ for all $x$ Find $f''(x)$ $$f''(x)=(x^2)'f(x)+x^2f'(x)$$ $$f''(x)=2xf(x)+x^2f'(x)$$ $$f''(x)=2xf(x)+x^2(x^2f(x))$$ $$f''(x)=2xf(x)+x^4f(x)$$ So, $$f''(2)=2\times2f(2)+2^4f(2)$$ $$f''(2)=4\times10+16\times10$$ $$f''(2)=200$$
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