Answer
$f'(x)=e^{x}(3x^{2}+x-5)$
Work Step by Step
$f(x)=(3x^{2}-5x)e^{x}$
Differentiate by applying the product rule:
$f'(x)=(3x^{2}-5x)(e^{x})'+(e^{x})(3x^{2}-5x)'=...$
$...=(3x^{2}-5x)(e^{x})+(e^{x})(6x-5)=...$
Take out common factor $e^{x}$:
$...=e^{x}(3x^{2}-5x+6x-5)=e^{x}(3x^{2}+x-5)$
$f'(x)=e^{x}(3x^{2}+x-5)$
