Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Review - Exercises - Page 268: 75


$f'(x) = g'(e^x)\cdot e^x$

Work Step by Step

Let $h(x) = e^x$ $h'(x) = e^x$ We can find $f'$: $f(x) = g(e^x)$ $f(x) = g(h(x))$ $f'(x) = g'(h(x))~\cdot h'(x)$ $f'(x) = g'(e^x)\cdot e^x$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.