Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 2 - Section 2.4 - The Precise Definition of a Limit - 2.4 Exercises: 13

Answer

a) $\delta = 0.025$ b) $\delta = 0.0025$

Work Step by Step

a) Let $\epsilon = 0.1$ $|4x-8| = 4|x-2|\lt 0.1$ $|x-2|\lt 0.025$ $\therefore \delta = 0.025$ b) Let $\epsilon = 0.01$ $|4x-8| = 4|x-2|\lt 0.01$ $|x-2|\lt 0.0025$ $\therefore \delta = 0.0025$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.