Chapter 2 - Section 2.4 - The Precise Definition of a Limit - 2.4 Exercises - Page 114: 13

a) $\delta = 0.025$ b) $\delta = 0.0025$

a) Let $\epsilon = 0.1$ $|4x-8| = 4|x-2|\lt 0.1$ $|x-2|\lt 0.025$ $\therefore \delta = 0.025$ b) Let $\epsilon = 0.01$ $|4x-8| = 4|x-2|\lt 0.01$ $|x-2|\lt 0.0025$ $\therefore \delta = 0.0025$