Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 2 - Section 2.3 - Calculating Limits Using the Limit Laws - 2.3 Exercises - Page 102: 13


$\lim\limits_{x \to 5}\dfrac{x^{2}-5x+6}{x-5}=\infty$

Work Step by Step

Apply direct substitution first: $\lim\limits_{x \to 5}\dfrac{x^{2}-5x+6}{x-5}=\dfrac{5^{2}-5(5)+6}{5-5}=\dfrac{6}{0}=\infty$
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