## Calculus: Early Transcendentals 8th Edition

a) 69.6 $\frac{heartbeats}{minute}$ b) 71.75 $\frac{heartbeats}{minute}$ c) 71 $\frac{heartbeats}{minute}$ d) 66 $\frac{heartbeats}{minute}$ Conclusion: We can find the slope at t = 42 by the average of the closest slopes which are t = 40 and t = 44, so m = $\frac{71+66}{2}$ = 68.5 $\frac{heartbeats}{minute}$
To find the slopes calculate by: m = $\frac{\frac{heartbeats}{minute}_{tf} -\frac{heartbeats}{minute}_{ti} }{tf-ti}$ a) m = $\frac{2948-2530}{42-36}$ b) m = $\frac{2948-2661}{42-38}$ c) m = $\frac{2948-2806}{42-40}$ d) m = $\frac{3080 - 2948}{44 - 42}$