Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 2 - Review - Concept Check - Page 165: 2

Answer

See explanation

Work Step by Step

Let's describe several ways in which a limit can fail to exist. Illustrate with sketches. The given definition of a limit is: $\lim\limits_{x \to a}f(x)=L$ if and only if $\lim\limits_{x \to a^-}f(x)= \lim\limits_{x \to a^+}f(x)=L$. Thus the limit will fail if $\lim\limits_{x \to a^-}f(x)\neq\lim\limits_{x \to a^+}f(x)$. There are several ways for this to occur but here are some examples: 1) The left-hand and right-hand limits are not equal (jump discontinuity) $\lim\limits_{x \to a^-}f(x)= L_1$ and $\lim\limits_{x \to a^+}f(x)=L_2$ where $L_1 \neq L_2$ 2) The function increases or decreases without bound (infinite discontinuity) $\lim\limits_{x \to a^-}f(x)= \infty$ and $\lim\limits_{x \to a^+}f(x)=-\infty$ creating an infinite discontinuity. 3) The function oscillates endlessly (oscillatory discontinuity) The function keeps swinging between values and never settles. Example: $f(x)=\sin \frac{1}{x}$ as $x\rightarrow 0$
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