Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Section 14.3 - Partial Derivatives - 14.3 Exercise - Page 924: 21

Answer

$f_x=\frac{1}{y}$, $f_y=\frac{-x}{y^2}$.

Work Step by Step

$f(x,y)=\frac{x}{y}$ In order to find $f_x$ we treat $y$ as a constant and differentiate with respect to $x$. $f_x=\frac{1}{y}$ In order to find $f_y$ we treat $x$ as a constant and differentiate with respect to $y$. $f_y=\frac{-x}{y^2}$
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