Chapter 14 - Section 14.2 - Limits and Continuity - 14.2 Exercise - Page 911: 34

{$(x,y) | x-y \gt -1$}

As we are given that $G(x,y)=ln(1+x-y)$ The function $G(x,y)=ln(1+x-y)$ represents a logarithmic function which is undefined for negative numbers. Thus, $ 1+x-y \gt 0$ or, $x-y \gt -1$ or, $x-y \gt -1$ This means that $x \gt y-1$ Hence, {$(x,y) | x-y \gt -1$}