Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Review - Exercises - Page 984: 45

Answer

$-\dfrac{4}{5}$

Work Step by Step

Our aim is to determine the directional derivative. In order to find it we have to use the expression: $D_uf(x,y)=f_x(x,y)m+f_y(x,y)n$ Given: $f(x,y)=x^2e^{-y}; (-2,0)$ and in the direction towards the point $(2,-3)$ $D_uf(x,y)=2xe^{-y}\dfrac{4}{5}-x^2e^{-y}\dfrac{-3}{5}$ This implies: From the given data, we have : $(x,y)=$ $(-2,0)$ $D_uf(0,1)=2(-2)e^{0}\dfrac{4}{5}-(-2)^2e^{0}\dfrac{-3}{5}=-\dfrac{4}{5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.