Answer
$=\frac{2}{3}$
Work Step by Step
From direct substitution, we have
$\lim\limits_{(x,y) \to (1,1)}\frac{2xy}{x^2+2y^2}=\frac{2(1)(1)}{(1)^2+2(1)^2}$
$=\frac{2}{3}$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 14 - Review - Exercises - Page 982: 9
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