Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 13 - Section 13.1 - Vector Functions and Space Curves - 13.1 Exercises - Page 853: 2

Answer

$(0, 2) \cup (2,\infty)$

Work Step by Step

First, we must find where our limiting components are defined: $ln \ t$ is defined when $t>0$ The denominator $t-2$ is defined when $t\ne2$ Looking at these components, we can see our domain is limited to $(0, 2) \cup (2,\infty)$.
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