Answer
Diagonal Length: $\sqrt{x^2+y^2+z^2}=\sqrt{2^2+3^2+5^2}=\sqrt{38}=6.164$
Work Step by Step
Diagonal Length: $\sqrt{x^2+y^2+z^2}=\sqrt{2^2+3^2+5^2}=\sqrt{38}=6.164$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 12 - Section 12.1 - Three-Dimensional Coordinate Systems - 12.1 Exercises - Page 796: 4
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