Answer
True
Work Step by Step
Since, $u.v=u_{1}v_{1}+u_{2}v_{2}+u_{3}v_{3}$ and
$v.u=v_{1}u_{1}+v_{2}u_{2}+v_{2}u_{2}$
Consider $u=\lt 1,0,0\gt$ and $v=\lt 0,1,0\gt$
$u.v=1*0+0*1=0+0*0=0$
and
$v.u=0*1+1*0+0*0=0$
Thus, $u.v= v.u$
Hence, the statement is true.