Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 11 - Section 11.7 - Strategy for Testing Series - 11.7 Exercises - Page 746: 22

Answer

Divergent

Work Step by Step

$$\lim\limits_{k\to\infty}|a_k|=\lim\limits_{k\to\infty}\left|\frac{1}{2+\sin{k}}\right|=\lim\limits_{k\to\infty}\frac{1}{2+|\sin{k}|}$$ The $|\sin{k}|$ oscillates between $0$ and $1$; therefore, the series oscillates between $\frac{1}{2}$ and $\frac{1}{3}$. Because the limit varies between two answers, it does not exist, thus the series $\sum_{n=1}^{\infty}\frac{1}{2+\sin{k}}$ is divergent.
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