Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 11 - Section 11.6 - Absolute Convergence and the Ratio and Root Tests - 11.6 Exercises - Page 743: 33

Answer

Absolutely convergent

Work Step by Step

By Ratio Test, we have $\lim_{n\to\infty}\biggl| \frac{9^{n+1}}{(n+1)10^{n+2}}\frac{n10^{n+1}}{9^n}\biggr|=\lim_{n\to\infty}\biggl|\frac{9}{10}\frac{n}{n+1}\biggr|=\frac{9}{10}$ Since the limit $ < 1$, the series is absolutely convergent by Ratio Test
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