Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 11 - Problems Plus - Problems: 2

Answer

$x\ne -1,1$

Work Step by Step

$f(x)=1,x\gt 1$ $F(1)=0$ $f(x)=-1$ $-1\lt x \lt 1$ $f(-1)=0$ $f(x)=1, x\lt 1$ Thus, $x\ne -1,1$
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