Answer
3
Work Step by Step
$1+\frac{1}{2}+\frac{1}{3}+...=\Sigma_{p=0}^\infty\Sigma_{q=0}^\infty\dfrac{1}{2^p3^q}$
$=\frac{1}{1-1/2}\frac{1}{1-1/3}$
$=3$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 11 - Problems Plus - Problems - Page 788: 6
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