Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.6 - Conic Sections in Polar Coordinates - 10.6 Exercises - Page 688: 2

Answer

$\dfrac{3}{1- \cos \theta}$

Work Step by Step

The polar equation of a conic with eccentricity $e$ and directrix $x=d$ can be written as: $r=\dfrac{ed}{1-e \cos \theta}$ ....(1) Given: Directrix , $x=-3$ The conic will be a parabola when $e = 1$ Thus, the equation (1) can be written as: $r=\dfrac{ed}{1-e \cos \theta}=\dfrac{(1)(3)}{1-(1)\cos \theta}=\dfrac{3}{1- \cos \theta}$
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