Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.3 - Polar Coordinates - 10.3 Exercises - Page 668: 68

Answer

The curve $$ r=\sqrt {1-0.8\sin^{2}\theta} $$ is graphed in the figure and the parameter interval is $[0, 2\pi]$

Work Step by Step

The curve $$ r=\sqrt {1-0.8\sin^{2}\theta} $$ is graphed in the figure and the parameter interval is $[0, 2\pi]$
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