Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.3 - Polar Coordinates - 10.3 Exercises - Page 667: 23



Work Step by Step

$y=1+3x$ We know that: $sin\theta=y/r$, so $y=rsin\theta$ We also know that: $cos\theta=x/r$, so $x=rcos\theta$ Substituting for $x$ and $y$, we get: $rsin\theta=1+3rcos\theta$ $rsin\theta-3rcos\theta=1$ $r(sin\theta-3cos\theta)=1$ $r=\frac{1}{sin\theta-3cos\theta}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.