Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Review - True-False Quiz - Page 689: 6



Work Step by Step

Given: $x^{2}+y^{2}=4$ and $r=2 $ or $r^{2}=4$ and $x=2sin3t,y=2cos3t$ The Cartesian equation is $x^{2}+y^{2}=r^{2}$ Then $x^{2}+y^{2}=(2sin3t)^{2}+(2cos3t)^{2}$ $=4sin^{2}3t+4cos^{2}3t$ $=4(sin^{2}3t+cos^{2}3t)$ $=4(1)$ Therefore, $x^{2}+y^{2}=4$ Hence, the given statement is true.
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