Answer
The light is 4 times brighter.
Work Step by Step
Let the initial distance from the lamp be $2d$.
$f(2d)=k(2d)^{-2}=\frac{k}{4d^{2}}$
Final distance = d.
$f(d)=kd^{-2}=4\times\frac{k}{4d^{2}}$
$\therefore$ The light is 4 times brighter.
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Section 1.2 - Mathematical Models: A Catalog of Essential Functions. - 1.2 Exercises - Page 36: 29
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