## Calculus: Early Transcendentals 8th Edition

The domain of the function is $x$ ≠ $\frac{\pi}{2}$ + $k$2$\pi$
1 - $sinx$ ≠ 0 $sinx$ ≠ 1 $x$ $\ne$ $\frac{\pi}{2}$ + $k$2$\pi$ The domain of the function is $x$ ≠ $\frac{\pi}{2}$ + $k$2$\pi$