## Calculus: Early Transcendentals 8th Edition

$f(-x)=1+3(-x)^{3}-(-x)^{5}=1-3x^{3}+x^{5}\ne \pm[1+3x^{3}-x^{5}]$ $f(-x)\ne \pm f(x)$ $\therefore f(x)$ is neither odd nor even.