Answer
$x\leq$(bc-b)/a
Work Step by Step
$(ax+b)/c\leq$b
$ax+b\geq$bc (since $c\lt0$)
$ax\geq$bc-b
$x\leq$(bc-b)/a (since $a\lt0$)
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
APPENDIX A - Numbers, Inequalities, and Absolute Values - A Exercises - Page A10: 60
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