Answer
\[\begin{align}
& \left. a \right){{10}^{2}}{{\left( \ln 10 \right)}^{0}}+{{10}^{2}}\left( \ln 10 \right)\left( x-2 \right)+\frac{{{10}^{2}}}{2!}{{\left( \ln 10 \right)}^{2}}{{\left( x-2 \right)}^{2}}+ \\
& +\frac{{{10}^{2}}{{\left( \ln 10 \right)}^{3}}}{3!}{{\left( x-2 \right)}^{3}} \\
& \left. b \right)\sum\limits_{k=0}^{\infty }{\frac{{{10}^{2}}{{\left( \ln 10 \right)}^{k}}{{\left( x-2 \right)}^{k}}}{k!}} \\
\end{align}\]
Work Step by Step
\[\begin{align}
& f\left( x \right)={{10}^{x}},\text{ }a=2 \\
& \text{Using the definition of Taylor series for a function}\left( page\,685 \right) \\
& \sum\limits_{k=0}^{\infty }{\frac{{{f}^{\left( k \right)}}\left( a \right)}{k!}{{\left( x-a \right)}^{k}}}\text{ }\left( \mathbf{1} \right) \\
& =f\left( a \right)+f'\left( a \right)\left( x-a \right)+\frac{f''\left( a \right)}{2!}{{\left( x-a \right)}^{2}}+\cdots \\
& \text{Calculate some derivatives and their value at }x=2 \\
& f\left( x \right)={{10}^{x}}\to f\left( 2 \right)={{10}^{2}} \\
& f'\left( x \right)={{10}^{x}}\left( \ln 10 \right)\to f\left( 2 \right)={{10}^{2}}\left( \ln 10 \right) \\
& f''\left( x \right)={{10}^{x}}{{\left( \ln 10 \right)}^{2}}\to f\left( 2 \right)={{10}^{2}}{{\left( \ln 10 \right)}^{2}} \\
& f''\left( x \right)={{10}^{x}}{{\left( \ln 10 \right)}^{3}}\to f\left( 2 \right)={{10}^{2}}{{\left( \ln 10 \right)}^{3}} \\
& \\
& \left. a \right)\text{ Substituting the previous result into the formula }\left( \mathbf{1} \right). \\
& \left( \text{Using the nonzero coefficients} \right) \\
& =\frac{{{10}^{2}}}{0!}{{\left( x-2 \right)}^{0}}+\frac{{{10}^{2}}\left( \ln 10 \right)}{1!}\left( x-2 \right)+\frac{{{10}^{2}}{{\left( \ln 10 \right)}^{2}}}{2!}{{\left( x-2 \right)}^{2}} \\
& +\frac{{{10}^{2}}{{\left( \ln 10 \right)}^{3}}}{3!}{{\left( x-2 \right)}^{3}} \\
& \text{Simplifying} \\
& ={{10}^{2}}+{{10}^{2}}\left( \ln 10 \right)\left( x-2 \right)+\frac{{{10}^{2}}}{2!}{{\left( \ln 10 \right)}^{2}}{{\left( x-2 \right)}^{2}} \\
& +\frac{{{10}^{2}}{{\left( \ln 10 \right)}^{3}}}{3!}{{\left( x-2 \right)}^{3}} \\
& \\
& \left. b \right)\text{ Rewrite the power series} \\
& ={{10}^{2}}{{\left( \ln 10 \right)}^{0}}+{{10}^{2}}\left( \ln 10 \right)\left( x-2 \right)+\frac{{{10}^{2}}}{2!}{{\left( \ln 10 \right)}^{2}}{{\left( x-2 \right)}^{2}} \\
& +\frac{{{10}^{2}}{{\left( \ln 10 \right)}^{3}}}{3!}{{\left( x-2 \right)}^{3}} \\
& \text{Using summation notation}\text{, we obtain} \\
& =\sum\limits_{k=0}^{\infty }{\frac{{{10}^{2}}{{\left( \ln 10 \right)}^{k}}{{\left( x-2 \right)}^{k}}}{k!}} \\
\end{align}\]