Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 7 - Integration Techniques - 7.6 Other Integration Strategies - 7.6 Exercises: 13

Answer

\[\begin{gathered} \frac{{2\sqrt {4x + 1} }}{4} + C \hfill \\ \hfill \\ \end{gathered} \]

Work Step by Step

\[\begin{gathered} \int_{}^{} {\frac{x}{{\sqrt {4x + 1} }}dx} \hfill \\ \hfill \\ use\,\,the\,\,\,\,formula \hfill \\ \hfill \\ \int {\frac{{dx}}{{\sqrt {ax + b} }}} dx = \frac{{2\sqrt {ax + b} }}{a} + C \hfill \\ \hfill \\ with\,\,a = 4\,\,and\,\,b = 1 \hfill \\ \hfill \\ then \hfill \\ \hfill \\ \int {\frac{{dx}}{{\sqrt {4x + 1} }}} = \frac{{2\sqrt {4x + 1} }}{4} + C \hfill \\ \end{gathered} \]
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