Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 6 - Applications of Integration - 6.3 Volume by Slicing - 6.3 Exercises - Page 431: 19

Answer

$\dfrac{15 \pi}{32}$

Work Step by Step

Since, the vertical slices solid are circular discs , so we will use the disk method to compute the volume of revolution of the curve. The volume of revolution of the curve can be expressed as: $V=\pi \int_p^q [f(x)]^2 dx\\=\pi \int_0^{\ln 4} (e^{-x})^2 \ dx \\= \pi \int_0^{\ln 4} e^{-2x} \ dx \\=\pi [\dfrac{-e^{-2x}}{2}]_0^{\ln 4} \\=\dfrac{\pi}{2} (1-e^{\ln 4^{-2}}) \\=\dfrac{15 \pi}{32}$
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