Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.9 Antiderivatives - 4.9 Exercises - Page 238: 28

Answer

$$12{m^5} - \frac{{50}}{3}{m^3} + C$$

Work Step by Step

$$\eqalign{ & \int {5m\left( {12{m^3} - 10n} \right)} dm \cr & {\text{multiply}} \cr & \int {\left( {60{m^4} - 50{m^2}} \right)} dm \cr & {\text{use power rule for indefinite integrals}} \cr & = \frac{{60{m^{4 + 1}}}}{{4 + 1}} - \frac{{50{m^{2 + 1}}}}{{2 + 1}} + C \cr & = \frac{{60{m^5}}}{5} - \frac{{50{m^3}}}{3} + C \cr & {\text{simplify}} \cr & = 12{m^5} - \frac{{50}}{3}{m^3} + C \cr & \cr & \cr & {\text{check the antiderivative by differentiation}} \cr & {\text{ = }}\frac{d}{{ds}}\left( {12{m^5} - \frac{{50}}{3}{m^3} + C} \right) \cr & = 12\left( 5 \right){m^4} - \frac{{50}}{3}\left( 3 \right){m^2} + 0 \cr & = 60{m^4} - 50{m^2} \cr & {\text{factor}} \cr & = 5m\left( {12{m^3} - 10m} \right) \cr} $$
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