Calculus: Early Transcendentals (2nd Edition)

$\frac{d}{dx}(\frac{f(x)}{g(x)})$ evaluated @ x=2 $=\frac{g(x)f'(x)-f(x)g'(x)}{g(x)^{2}}$ $=\frac{g(2)f'(2)-f(2)g'(2)}{g(2)^{2}}$ $=\frac{2\times5-4\times4}{2^{2}}$ $=\frac{-6}{4}$ $=-1.5$