Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.2 Working with Derivatives - 3.2 Exercises - Page 141: 2


Because the function be decreasing when its both positive or negative.

Work Step by Step

When $f'(x)<0$ then the function is decreasing. But the function can be decreasing no matter if it is positive or negative so $f(x)$ can be both greater than zero and less than zero.
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