#### Answer

$f'(x) = \sin^{-1}x + \frac{x}{\sqrt {1-x^2}}$

#### Work Step by Step

$f(x) = x\sin^{-1}x$
Product Rule:
$f'(x) = x \times \frac{1}{\sqrt {1-x^2}} + (1)\sin^{-1}x = \sin^{-1}x + \frac{x}{\sqrt {1-x^2}}$

Published by
Pearson

ISBN 10:
0321947347

ISBN 13:
978-0-32194-734-5

$f'(x) = \sin^{-1}x + \frac{x}{\sqrt {1-x^2}}$

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