## Calculus: Early Transcendentals (2nd Edition)

$\lim\limits_{x \to 1}$ $\frac{x^{2}-1}{x-1}$ = $\lim\limits_{x \to 1}$ $\frac{(x-1)(x+1)}{x-1}$ = $\lim\limits_{x \to 1}$ x+1 = 1+1 = 2