Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 12 - Functions of Several Veriables - 12.7 Tangent Planes and Linear Approximation - 12.7 Exercises - Page 935: 3

Answer

$${F_x}\left( {a,b,c} \right)\left( {x - a} \right) + {F_y}\left( {a,b,c} \right)\left( {y - b} \right) + {F_z}\left( {z - c} \right) = 0$$

Work Step by Step

$$\eqalign{ & F\left( {x,y,z} \right) = 0,{\text{ Point }}\left( {\underbrace a_{{x_1}},\underbrace b_{{y_1}},\underbrace c_{{z_1}}} \right) \cr & {\text{The equation of the Tangent Plane for }}F\left( {x,y,z} \right) = 0{\text{ at the}} \cr & {\text{point }}\left( {\underbrace a_{{x_1}},\underbrace b_{{y_1}},\underbrace c_{{z_1}}} \right){\text{is: }}\left( {{\text{See page 930}}} \right) \cr & {F_x}\left( {a,b,c} \right)\left( {x - a} \right) + {F_y}\left( {a,b,c} \right)\left( {y - b} \right) + {F_z}\left( {z - c} \right) = 0 \cr} $$
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