Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 12 - Functions of Several Veriables - 12.3 Limits and Continuity - 12.3 Exercises - Page 894: 66

Answer

$$0$$

Work Step by Step

$$\eqalign{ & \mathop {\lim }\limits_{\left( {u,v} \right) \to \left( { - 1,0} \right)} \frac{{uv{e^{ - v}}}}{{{u^2} + {v^2}}} \cr & {\text{Evaluating the limit}} \cr & \mathop {\lim }\limits_{\left( {u,v} \right) \to \left( { - 1,0} \right)} \frac{{uv{e^{ - v}}}}{{{u^2} + {v^2}}} = \frac{{\left( { - 1} \right)\left( 0 \right){e^{ - 0}}}}{{{{\left( { - 1} \right)}^2} + {{\left( 0 \right)}^2}}} \cr & {\text{Simplifying}} \cr & \mathop {\lim }\limits_{\left( {u,v} \right) \to \left( { - 1,0} \right)} \frac{{uv{e^{ - v}}}}{{{u^2} + {v^2}}} = \frac{{\left( { - 1} \right)\left( 0 \right)\left( 1 \right)}}{{1 + 0}} \cr & \mathop {\lim }\limits_{\left( {u,v} \right) \to \left( { - 1,0} \right)} \frac{{uv{e^{ - v}}}}{{{u^2} + {v^2}}} = 0 \cr} $$
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