Answer
$D=\{(x,y)\in R^2: x^2+y^2\gt 25\}$.
Work Step by Step
Since $f(x,y)=\frac{1}{\sqrt{x^2+y^2-25}}$ is defined for all $x,y$ satisfying that $ x^2+y^2\gt 25$. Hence the domain of $f$ is the region $D=\{(x,y)\in R^2: x^2+y^2\gt 25\}$.
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 12 - Functions of Several Veriables - 12.2 Graphs and Level Curves - 12.2 Exercises - Page 882: 14
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